2025 NEW C_ABAPD_2309 TEST SYLLABUS | LATEST C_ABAPD_2309 100% FREE EXAM QUESTIONS ANSWERS

2025 New C_ABAPD_2309 Test Syllabus | Latest C_ABAPD_2309 100% Free Exam Questions Answers

2025 New C_ABAPD_2309 Test Syllabus | Latest C_ABAPD_2309 100% Free Exam Questions Answers

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SAP Certified Associate - Back-End Developer - ABAP Cloud Sample Questions (Q82-Q87):

NEW QUESTION # 82
In this nested join below in which way is the join evaluated?

  • A. From the right to the left in the order of the tables:
    1.
    b is joined with c.
    2.
    b is joined with a.
  • B. From the left to the right in the order of the tables:
    1.
    a is joined with b
    2.
    b is joined with c
  • C. From the top to the bottom in the order of the on conditions
    1.
    b is joined with c
    2.
    a is joined with b
  • D. From the bottom to the top in the order of the on conditions:
    1.
    a is joined with b
    2.
    b is joined with c

Answer: C

Explanation:
The nested join is evaluated from the top to the bottom in the order of the ON conditions. This means that the join expression is formed by assigning each ON condition to the directly preceding JOIN from left to right. The join expression can be parenthesized implicitly or explicitly to show the order of evaluation. In this case, the implicit parentheses are as follows:
SELECT * FROM (a INNER JOIN (b INNER JOIN c ON b~c = c~c) ON a~b = b~b) This means that the first join expression is b INNER JOIN c ON b~c = c~c, which joins the columns of tables b and c based on the condition that b~c equals c~c. The second join expression is a INNER JOIN (b INNER JOIN c ON b~c = c~c) ON a~b = b~b, which joins the columns of table a and the result of the first join expression based on the condition that a~b equals b~b. The final result set contains all combinations of rows from tables a, b, and c that satisfy both join conditions.


NEW QUESTION # 83
Which of the following string functions are predicate functions? Note: There are 2 correct answers to this question.

  • A. matchesQ
  • B. contains_any_of()
  • C. count_any_of()
  • D. find_any_not_of()

Answer: A,B

Explanation:
String functions are expressions that can be used to manipulate character-like data in ABAP. String functions can be either predicate functions or non-predicate functions. Predicate functions are string functions that return a truth value (true or false) for a condition of the argument text. Non-predicate functions are string functions that return a character-like result for an operation on the argument text1.
The following string functions are predicate functions:
* B. contains_any_of(): This function returns true if the argument text contains at least one of the characters specified in the character set. For example, the following expression returns true, because the text 'ABAP' contains at least one of the characters 'A', 'B', or 'C':
contains_any_of( val = 'ABAP' set = 'ABC' ).
* D. matches(): This function returns true if the argument text matches the pattern specified in the regular expression. For example, the following expression returns true, because the text 'ABAP' matches the pattern that consists of four uppercase letters:
matches( val = 'ABAP' regex = '[A-Z]{4}' ).
The following string functions are not predicate functions, because they return a character-like result, not a truth value:
* A. find_any_not_of(): This function returns the position of the first character in the argument text that is not contained in the character set. If no such character is found, the function returns 0. For example, the following expression returns 3, because the third character of the text 'ABAP' is not contained in the character set 'ABC':
find_any_not_of( val = 'ABAP' set = 'ABC' ).
* C. count_any_of(): This function returns the number of characters in the argument text that are
* contained in the character set. For example, the following expression returns 2, because there are two characters in the text 'ABAP' that are contained in the character set 'ABC':
count_any_of( val = 'ABAP' set = 'ABC' ).
References: 1: String Functions - ABAP Keyword Documentation


NEW QUESTION # 84
Exhibit:
With Icl_super being superclass for Icl_subl and Icl_sub2 and with methods subl_methl and sub2_methl being subclass-specific methods of Id_subl or Icl_sub2, respectivel. What will happen when executing these casts?
Note:
There are 2 correct answers to this question

  • A. go_sub2 = CAST #(go_super). will not work. ] go sub2->sub2 meth 1(...). will work
  • B. go subl = CAST # go super), will not work
  • C. go_sub2 = CAST # go super), will work. go_subl CAST #go_super), will work
  • D. go_subl->subl_meth !(...)* w'll work.

Answer: B,D

Explanation:
The following are the explanations for each statement:
* A: This statement is correct. go_subl = CAST #(go_super) will not work. This is because go_subl is a data object of type REF TO cl_subl, which is a reference to the subclass cl_subl. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_subl, but this is not possible, as go_super is not pointing to an instance of cl_subl, but to an instance of cl_super. Therefore, the CAST operator will raise an exception CX_SY_MOVE_CAST_ERROR at runtime12
* B: This statement is incorrect. go_sub2 = CAST #(go_super) will work. go_subl = CAST #(go_super) will not work. This is because go_sub2 is a data object of type REF TO cl_sub2, which is a reference to the subclass cl_sub2. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_sub2, and this is possible, as go_super is pointing to an instance of cl_sub2, which is a subclass of cl_super.
* Therefore, the CAST operator will assign the reference of go_super to go_sub2 without raising an exception. However, the CAST operator will not work for go_subl, as explained in statement A12
* C: This statement is incorrect. go_sub2 = CAST #(go_super) will work. go_sub2->sub2_meth1(...) will not work. This is because go_sub2 is a data object of type REF TO cl_sub2, which is a reference to the subclass cl_sub2. go_super is a data object of type REF TO cl_super, which is a reference to the superclass cl_super. The CAST operator is used to perform a downcast or an upcast of a reference variable to another reference variable of a compatible type. A downcast is a conversion from a more general type to a more specific type, while an upcast is a conversion from a more specific type to a more general type. In this case, the CAST operator is trying to perform a downcast from go_super to go_sub2, and this is possible, as go_super is pointing to an instance of cl_sub2, which is a subclass of cl_super.
Therefore, the CAST operator will assign the reference of go_super to go_sub2 without raising an exception. However, the method call go_sub2->sub2_meth1(...) will not work, as sub2_meth1 is a subclass-specific method of cl_sub2, which is not inherited by cl_super. Therefore, the method call will raise an exception CX_SY_DYN_CALL_ILLEGAL_METHOD at runtime123
* D: This statement is correct. go_subl->subl_meth1(...) will work. This is because go_subl is a data object of type REF TO cl_subl, which is a reference to the subclass cl_subl. subl_meth1 is a subclass-specific method of cl_subl, which is not inherited by cl_super. Therefore, the method call go_subl->subl_meth1(...) will work, as go_subl is pointing to an instance of cl_subl, which has the method subl_meth1123 References: NEW - ABAP Keyword Documentation, CAST - ABAP Keyword Documentation, Method Call - ABAP Keyword Documentation


NEW QUESTION # 85
Which internal table type allows unique and non-unique keys?

  • A. Hashed
  • B. Standard
  • C. Sorted

Answer: B

Explanation:
Explanation
The internal table type that allows both unique and non-unique keys is the standard table. A standard table has an internal linear index that can be used to access the table entries. The key of a standard table is always non-unique, which means that the table can contain duplicate entries. However, the system does not check the uniqueness of the key when inserting new entries, so the programmer can ensure that the key is unique by using appropriate logic. A standard table can be accessed either by using the table index or the key, but the response time for key access is proportional to the table size.
The other two internal table types, sorted and hashed, do not allow non-unique keys. A sorted table is filled in sorted order according to the defined table key, which must be unique. A sorted table can be accessed either by using the table index or the key, but the response time for key access is logarithmically proportional to the table size. A hashed table can only be accessed by using a unique key, which must be specified when declaring the table. A hashed table has no index, and the response time for key access is constant, regardless of the table size.
References: Internal Tables - ABAP Keyword Documentation, SAP ABAP: Types Of Internal Table Declaration - dan852.com


NEW QUESTION # 86
Given the following Core Data Service View Entity Data Definition:
1 @AccessControl.authorizationCheck: #NOT_REQUIRED
2 DEFINE VIEW ENTITY demo_flight_info_join
3 AS SELECT
4 FROM scarr AS a
5 LEFT OUTER JOIN scounter AS c
6 LEFT OUTER JOIN sairport AS p
7 ON p.id = c.airport
8 ON a.carrid = c.carrid
9 {
10 a.carridAS carrier_id,
11 p.idAS airport_id,
12 c.countnumAS counter_number
13 }
In what order will the join statements be executed?

  • A. scarr will be joined with sairport first and the result will be joined with scounter.
  • B. scarr will be joined with scounter first and the result will be joined with sairport.
  • C. sairport will be joined to scounter first and the result will be joined with scarr.
  • D. scounter will be joined to sairport first and the result will be joined with scarr.

Answer: B

Explanation:
Explanation
The order in which the join statements will be executed is:
scarr will be joined with scounter first and the result will be joined with sairport.
This is because the join statements are nested from left to right, meaning that the leftmost data source is joined with the next data source, and the result is joined with the next data source, and so on. The join condition for each pair of data sources is specified by the ON clause that follows the data source name. The join type for each pair of data sources is specified by the join operator that precedes the data source name. In this case, the join operator is LEFT OUTER JOIN, which means that all the rows from the left data source are included in the result, and only the matching rows from the right data source are included. If there is no matching row from the right data source, the corresponding fields are filled with initial values1.
Therefore, the join statements will be executed as follows:
First, scarr AS a will be joined with scounter AS c using the join condition a.carrid = c.carrid. This means that all the rows from scarr will be included in the result, and only the rows from scounter that have the same value for the carrid field will be included. If there is no matching row from scounter, the countnum field will be filled with an initial value.
Second, the result of the first join will be joined with sairport AS p using the join condition p.id = c.airport. This means that all the rows from the first join will be included in the result, and only the rows from sairport that have the same value for the id field as the airport field from the first join will be included. If there is no matching row from sairport, the id field will be filled with an initial value.
References: 1: Join - ABAP Keyword Documentation


NEW QUESTION # 87
......

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